2^2x^2+2x=1/4^2x-40

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Solution for 2^2x^2+2x=1/4^2x-40 equation: 



2^2x^2+2x=1/4^2x-40

We move all terms to the left:

2^2x^2+2x-(1/4^2x-40)=0



Domain of the equation: 4^2x-40)!=0

x∈R



We add all the numbers together, and all the variables

2x+2^2x^2-(1/4^2x-40)=0

We get rid of parentheses

2x+2^2x^2-1/4^2x+40=0

We multiply all the terms by the denominator


2x*4^2x+2^2x^2*4^2x+40*4^2x-1=0

Wy multiply elements

8x^3+8x^4+160x^2-1=0

We do not support expression: x^3

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